**Java program for a square root or a number in Java**How to write a Java program to find the square root of a number is a common Java programming exercise that many institute use in there Java course along with Java program to print Fibonacci series and How to find Armstrong numbers in Java, which we have seen earlier. Java program for square root is also a popular question during college semester exams and various programming tests.

If you are
familiar with Java API then writing a Java program that can find the square root
of a number using java.lang.Math class is not difficult. You just
need to pass a double value and it returns a double which is the

*square root of the number*you passed.
In the next section, we will see the complete code example
of finding the square root of a number from the Java program. Another Java
coding questions which is very popular and related to programming exercise
is writing
Java program to find prime numbers, if you are going to appear in Java
interviews than its worth looking.

##
__How to find Square root of a number in Java__

As I said it's easy to calculate square root using java.lang.Math sqrt()
function but things can be a tricky question if the interviewer will ask you to write your
own sqrt() function during programming
interviews.

Well its not that easy to write sqrt() function
which can operate on double but one trick I use to remember the concept that
square of the square root must be either less than or equal to the number, you can use
that concept to write your own sqrt() method in any programming
language including Java.

Barring Java interviews, I suggest programmer use standard JDK library or open-source library like Spring, Apache etc for such common task because of the quality of code and amount of testing done of those libraries.

Btw, a basic knowledge of data structure and algorithms is needed and if you need to brush up then do so. If you need a resource, I highly recommend checking out

Barring Java interviews, I suggest programmer use standard JDK library or open-source library like Spring, Apache etc for such common task because of the quality of code and amount of testing done of those libraries.

Btw, a basic knowledge of data structure and algorithms is needed and if you need to brush up then do so. If you need a resource, I highly recommend checking out

**Data Structures and Algorithms: Deep Dive Using Java**course on Udemy. It's a hands-on course and covers all essential data structures.
It's also very affordable and you can get in just $10 on Udemy flash sales which happens every now and then.

###
__Java program to find the square root of a number__

Anyway, here we will see Java program for finding square root using the API method,

**package**test;

**import**java.util.Scanner;

/**

*

*

**Java program to find the square root of a number in Java**.

* This Java program example demonstrates using Math class

* sqrt() method to get the square root of a number in Java.

*

* @author java67

*/

**public**

**class**SquareRoot{

**public**

**static**

**void**main(

**String**args[]) {

*//Used to get input number for which square root to find*

**Scanner**scanner =

**new**

**Scanner**(

**System**.in);

**System**.out.println("Enter number to find square root in Java : ");

*//getting input number from user to calculate square root*

**double**square = scanner.nextDouble();

*//getting the square root of a number in Java*

**double**squareRoot =

**Math**.sqrt(square);

*//printing number and its square root in Java*

**System**.out.printf("Square root of number: %f is : %f %n" , square, squareRoot);

}

}

Output:

Enter number to find square root in Java :

64

The square root of a number: 64.000000 is: 8.000000

This was our

**Java program to find the square root of a number in Java**. It can find the square root of any floating-point number and you don’t need to only supply integers numbers. As I said use Java standard library methods to calculate square root but prepare with your own version of square root function if going for any programming interview.**Further Learning**

Data Structures and Algorithms: Deep Dive Using Java

Java Fundamentals: The Java Language

Complete Java Masterclass

Grokking the Coding Interview: Patterns for Coding Questions

Related

Thanks for reading this article so far. If you like this article then please share it with your friends and colleagues. If you have any questions or doubt then please let us know and I'll try to find an answer for you. As always suggestions, comments, innovative and better answers are most welcome.

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Thanks for reading this article so far. If you like this article then please share it with your friends and colleagues. If you have any questions or doubt then please let us know and I'll try to find an answer for you. As always suggestions, comments, innovative and better answers are most welcome.

**P. S.**- If you are looking for some Free Algorithms courses to improve your understanding of Data Structure and Algorithms, then you should also check the**Data Structure in Java**free course on Udemy. It's completely free and all you need to do is create a free Udemy account to enroll in this course.
In mathematics, a square root of a number a is a number y such that y2 = a, or, in other words, a number y whose square (the result of multiplying the number by itself, or y × y) is a.

ReplyDeleteWrite a Java program to find Square root of a number is common programming exercise for beginners in Java. Some people use it as practice and homework exercise to learn Java programming and

ReplyDeleteget familiar with Java API in particular java.lang.Math, which holds key method for various mathematical tasks.

thnk u

ReplyDeleteLET SOMEONE CORRECT THIS FOR ME. THANKS

ReplyDelete//java program for dept...........

//group 9

//serial no 44

//name1:

//name2:

//name3:

//name4

//name5

import javax.swing.JOptionPane;

public class CSCGP9 {

public static void main (String [] args){

float z, zl, c=0.0f ;

system.out.printLn ("S/N \t number \tsquare \tcube")n;

for(int k = 1; k<= 9; k++){

c=Float.parseFloat (JOptionpane.showInputDialog("Enter a number",0));

z=square(c);

zl=cube (c);

system.out.println(k+"\t"+c+"\t"+square(c)+"\t"+cube(c));

}

}

static Float square (float x){

return x*x;

}

static Float cube (float x){

return x*x*x;

}

}

C:\Users\student\Desktop\19>javac Sqr2.java

ReplyDeleteSqr2.java:10: error: possible loss of precision

float r=Math.sqrt(square);

^

required: float

found: double

1 error how to overcome this???

Hello @Annonymous, Math.sqrt() returns double, which is bigger data type than float hence you cannot store a double value to float variable. if you want you can use the cast operator e.g.

Deletefloat r= (float) Math.sqrt(square);

This will fix the problem.

You can change the float into double type.

DeleteJava program for finding nth root

ReplyDeleteIts too big see this is a very small one

ReplyDeleteimport java.util.*;

/*Java Program to find square, square root and cube of a given number*/

public class j5

{

public static void main(String args[]){

Scanner sc=new Scanner(System.in);

int num;

System.out.print("Enter an integer number: ");

num=sc.nextInt();

System.out.println("Square of "+ num + " is: "+ Math.pow(num, 2));

System.out.println("Cube of "+ num + " is: "+ Math.pow(num, 3));

System.out.println("Square Root of "+ num + " is: "+ Math.sqrt(num));

}

}

This is without using any math functions

ReplyDeleteimport java.util.Scanner;

public class SquareRoot {

public static void main(String[] args)

{

System.out.println("Enter the number to find the square root");

Scanner scr = new Scanner(System.in);

int Sqt=scr.nextInt();

for (int i=1;i<=Sqt;i++)

{

int reminder = Sqt%i;

if (reminder==0 && (Sqt/i)==i)

{

System.out.println("The Square root of "+Sqt+" is = "+i);

}

}

scr.close();

}

}