tag:blogger.com,1999:blog-694855878384792308.post6353417810293676955..comments2024-03-15T23:19:22.318-07:00Comments on Java67: How to Find Square Root of a Number in Java [Solved] - Example Tutorialjavin paulhttp://www.blogger.com/profile/15028902221295732276noreply@blogger.comBlogger10125tag:blogger.com,1999:blog-694855878384792308.post-52942760167248942722019-12-19T02:16:31.260-08:002019-12-19T02:16:31.260-08:00You can change the float into double type.You can change the float into double type.Bubulhttps://www.blogger.com/profile/03879402815043494961noreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-80702579626434840302019-08-12T02:39:33.538-07:002019-08-12T02:39:33.538-07:00This is without using any math functions
import j...This is without using any math functions<br /><br />import java.util.Scanner;<br /><br />public class SquareRoot {<br /> <br /> public static void main(String[] args) <br /> {<br /> <br /> System.out.println("Enter the number to find the square root");<br /> Scanner scr = new Scanner(System.in);<br /> int Sqt=scr.nextInt();<br /> <br /> for (int i=1;i<=Sqt;i++)<br /> {<br /> int reminder = Sqt%i;<br /> if (reminder==0 && (Sqt/i)==i)<br /> {<br /> System.out.println("The Square root of "+Sqt+" is = "+i);<br /> }<br /> }<br /> <br /> scr.close(); <br /> }<br />}<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-7413251656307845592019-02-28T10:23:37.558-08:002019-02-28T10:23:37.558-08:00Its too big see this is a very small one
import ja...Its too big see this is a very small one<br />import java.util.*;<br /> <br />/*Java Program to find square, square root and cube of a given number*/<br />public class j5 <br />{<br /> public static void main(String args[]){<br /> Scanner sc=new Scanner(System.in);<br /> int num;<br /><br /> System.out.print("Enter an integer number: ");<br /> num=sc.nextInt();<br /><br /> System.out.println("Square of "+ num + " is: "+ Math.pow(num, 2));<br /> System.out.println("Cube of "+ num + " is: "+ Math.pow(num, 3));<br /> System.out.println("Square Root of "+ num + " is: "+ Math.sqrt(num));<br /> }<br />}<br /><br />Anonymoushttps://www.blogger.com/profile/17833595475883800694noreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-67294563752188819682017-11-01T04:49:44.642-07:002017-11-01T04:49:44.642-07:00Java program for finding nth rootJava program for finding nth rootAnonymoushttps://www.blogger.com/profile/02144298485166074866noreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-51639486403863308812017-06-28T05:14:46.344-07:002017-06-28T05:14:46.344-07:00Hello @Annonymous, Math.sqrt() returns double, whi...Hello @Annonymous, Math.sqrt() returns double, which is bigger data type than float hence you cannot store a double value to float variable. if you want you can use the cast operator e.g. <br /><br />float r= (float) Math.sqrt(square);<br /><br />This will fix the problem. <br />javin paulhttps://www.blogger.com/profile/15028902221295732276noreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-73799871146993175592017-06-27T23:14:20.251-07:002017-06-27T23:14:20.251-07:00C:\Users\student\Desktop\19>javac Sqr2.java
Sqr...C:\Users\student\Desktop\19>javac Sqr2.java<br />Sqr2.java:10: error: possible loss of precision<br /> float r=Math.sqrt(square);<br /> ^<br /> required: float<br /> found: double<br />1 error how to overcome this???Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-28590709798260507132014-08-28T04:19:42.589-07:002014-08-28T04:19:42.589-07:00LET SOMEONE CORRECT THIS FOR ME. THANKS
//java pr...LET SOMEONE CORRECT THIS FOR ME. THANKS<br /><br />//java program for dept...........<br />//group 9<br />//serial no 44<br />//name1:<br />//name2:<br />//name3:<br />//name4<br />//name5<br />import javax.swing.JOptionPane;<br />public class CSCGP9 {<br /> public static void main (String [] args){<br />float z, zl, c=0.0f ;<br />system.out.printLn ("S/N \t number \tsquare \tcube")n;<br />for(int k = 1; k<= 9; k++){<br /> c=Float.parseFloat (JOptionpane.showInputDialog("Enter a number",0));<br /> z=square(c);<br /> zl=cube (c);<br />system.out.println(k+"\t"+c+"\t"+square(c)+"\t"+cube(c));<br />}<br />}<br />static Float square (float x){<br />return x*x;<br />}<br />static Float cube (float x){<br />return x*x*x;<br />}<br />}<br /><br /><br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-6495676202875849492013-08-07T06:14:22.734-07:002013-08-07T06:14:22.734-07:00thnk u
thnk u<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-85697612275522898732012-09-19T02:52:36.791-07:002012-09-19T02:52:36.791-07:00Write a Java program to find Square root of a numb...Write a Java program to find Square root of a number is common programming exercise for beginners in Java. Some people use it as practice and homework exercise to learn Java programming and<br />get familiar with Java API in particular java.lang.Math, which holds key method for various mathematical tasks.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-694855878384792308.post-22821809391198758642012-09-14T00:19:27.384-07:002012-09-14T00:19:27.384-07:00In mathematics, a square root of a number a is a n...In mathematics, a square root of a number a is a number y such that y2 = a, or, in other words, a number y whose square (the result of multiplying the number by itself, or y × y) is a.square and square roothttp://math.edurite.com/squares-and-square-roots-t2wmp.htmlnoreply@blogger.com